MIL-STD-209K APPENDIX B
The same equation can be applied to the other provisions.
COS(�) = hb/hbt ; hbt = hb/COS(�) = 58.5/COS(3.80) = 58.6 inches COS(�) = hc/hct ; hct = hc/COS(�) = 86.0/COS(3.80) = 86.2 inches COS(�) = hd/hdt ; hdt = hd/COS(�) = 85.6/COS(3.80) = 85.8 inches
K2 = S2 + h
2 - 2Sh
COS(SA)
at at
K = √S2 + h
2 - 2Sh
COS(SA)
at at
K = √1442 + 58.32 - 2(144)(58.3)COS(59.7°) = 125.2 inches
B.5.1.4 Determine VA, the angle of the slings with the vertical when the equipment is lifted.
h 2 = S2 + K2 - 2SKCOS(VA )
at a
VA = COS-1((S2 + K2 - h
2)/2SK)
VA = COS-1((1442 + 125.22 - 58.32)/2(144)(125.2)) = 23.70
VA = COS-1((S2 + K2 - h
2)/2SK)
VA = COS-1((1442 + 125.22 - 58.62)/2(144)(125.2)) = 23.90
VA = COS-1((S2 + K2 - h
2)/2SK)
VA = COS-1((1442 + 125.22 - 86.22)/2(144)(125.2)) = 36.50
VA = COS-1((S2 + K2 - h
2)/2SK)
VA = COS-1((1442 + 125.22 - 85.82)/2(144)(125.2)) = 36.30
B.5.1.5 Determine the vertical force component, V, at each provision.
Based on the assumption that the CG lies on the plane of the provisions, the horizontal distance between the provisions and the vertical axis of the CG when the equipment is
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