MIL-STD-209K APPENDIX C
C.4.1.1 Minimum required longitudinal design and ultimate loads. The longitudinal inertia force acting through the CG is:
4 x GW = 4 x 20,000 lb = 80,000 lb
Assume the inertia force will be balanced/restrained by the longitudinal components of the applicable tiedown provisions to restrict the movement of the item in the forward and aft directions.
a. To restrict movement in the forward direction, two provisions can be used:
3L 4L
= 80,000 lb
For this example, the provisions are not located symmetrically about the CG so the proportionate share of the load that is applied to each provision is not equal and is as follows:
S 4 x (T3L + T4L )
10 x 80,000
3L (S
3 + S4 )
= (5 +10) = 53,333 lb
S 3 x (T3L + T4L )
5 x 80,000
4L (S
3 + S4 )
= (5 +10) = 26,667 lb
b. To restrict movement in the aft direction, two provisions can be used:
T1L + T2L = 80,000 lb
For this example, the provisions are not located symmetrically about the CG so the proportionate share of the load that is applied to each provision is not equal and is as follows:
S 2 x (T1L + T2L )
10 x 80,000
1L (S
1 + S2 )
= (5 +10) = 53,333 lb
S1 x (T1L + T2L )
5 x 80,000
2L (S
1 + S2 )
= (5 +10) = 26,667 lb
Ultimate load requirements (1.5 x design limit load) are:
Forward U
= 1.5 x T
= 1.5 x 53,333 lb = 80,000 lb
Source: https://assist.dla.mil -- DCow-3nloaded: 2014-09-28T23:10Z Check the source to verify that this is the current version before use.
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