MIL-8TD-209K APPENDIX C
S 3
L 2
T = (S
+ S ) x (L
+ L )
x (T + T + T + T )
4v 3 4
5
4V = (5 + 10)
2 4
15
x (15 + 10)
x 40,000 = 8,000 lb
Each provision must withstand a vertical force (required design limit load) of 10,000 pounds applied in the downward direction. Ultimate load requirements (1.5 x design
limit load) are:
= 1.5 x T
= 1.5 x 10,667 = 16,000 lb
= 1.5 x T
= 1.5 x 5,333 = 8,000 lb
= 1.5 x T
= 1.5 x 16,000 = 24,000 lb
= 1.5 x T
= 1.5 x 8,000 = 12,000 lb
C.4.1.3 Minimum required lateral design limit and ultimate loads. The lateral inertia force acting through the CG is:
1.5 x GW = 1.5 x 20,000 lb = 30,000 lb
It should be assumed that this force will be restrained by the lateral force compo- nents of the tiedown provisions toward the left and right.
a. To restrict movement toward the right, two provisions can be used:
28 48
= 30,000 lb
For this example, the provisions are not located symmetrically about the CG so the proportionate share of the load that is applied to each provision is not equal and is as follows:
L4 x (T2S + T4S )
10 x 30,000
28 (L
2 + L4 )
= (15 + 10) = 12,000 lb
Source: https://assist.dla.mil -- DCow-5nloaded: 2014-09-28T23:10Z Check the source to verify that this is the current version before use.
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